Log(9x-2)-log(4x)=1

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Solution for Log(9x-2)-log(4x)=1 equation: 


Simplifying
Log(9x + -2) + -1log(4x) = 1

Reorder the terms:
goL(-2 + 9x) + -1log(4x) = 1
(-2 * goL + 9x * goL) + -1log(4x) = 1
(-2goL + 9goxL) + -1log(4x) = 1

Remove parenthesis around (4x)
-2goL + 9goxL + -1glo * 4x = 1

Reorder the terms for easier multiplication:
-2goL + 9goxL + -1 * 4glo * x = 1

Multiply -1 * 4
-2goL + 9goxL + -4glo * x = 1

Multiply glo * x
-2goL + 9goxL + -4glox = 1

Reorder the terms:
-4glox + -2goL + 9goxL = 1

Solving
-4glox + -2goL + 9goxL = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + -4glox + -2goL + 9goxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -4glox + -2goL + 9goxL = 0

The solution to this equation could not be determined.

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