Log(x)+log(2x-1)=1

Simple and best practice solution for Log(x)+log(2x-1)=1 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for Log(x)+log(2x-1)=1 equation:


Simplifying
Log(x) + log(2x + -1) = 1

Multiply goL * x
goxL + log(2x + -1) = 1

Reorder the terms:
goxL + glo(-1 + 2x) = 1
goxL + (-1 * glo + 2x * glo) = 1
goxL + (-1glo + 2glox) = 1

Reorder the terms:
-1glo + 2glox + goxL = 1

Solving
-1glo + 2glox + goxL = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + -1glo + 2glox + goxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -1glo + 2glox + goxL = 0

The solution to this equation could not be determined.

See similar equations:

| -112-(2y)=-24 | | 3a+4m+5y=28 | | 5x+3(2x)=33 | | Y+6(1)=5 | | s-(-13)=46 | | 4=2+2t | | 4(2-x)+5=-3(2x+3)-12 | | n/7-6=14 | | -(b+a)= | | 16cos^4(x)= | | 10(8+x)=260 | | w/-9=5 | | 16(x^3+4x)=0 | | -16p=-64 | | 15(a-7)=-7-8 | | 52x=150 | | 7(x+2)-4m=2(m+10) | | 16cos^4(x)-12cos^2(x)=-1 | | Y+6(-3)=5 | | y-(-6)=53 | | 5x+2d-2x=1 | | 5sinx-4=0 | | u/-9=(-9) | | 2(L+12)=36 | | 3y+2=1-7y | | X-2.4=5.1 | | (p-4)(p+3)=0 | | 16cos^4(x)-12cos^2(x)+1=0 | | 68=t+(-14) | | Z-15=30 | | u-(-14)=19 | | 4*[1-(4-15)/3] |

Equations solver categories