Log(x+1)(7x+7)=2

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Solution for Log(x+1)(7x+7)=2 equation: 


Simplifying
Log(x + 1)(7x + 7) = 2

Reorder the terms:
goL(1 + x)(7x + 7) = 2

Reorder the terms:
goL(1 + x)(7 + 7x) = 2

Multiply (1 + x) * (7 + 7x)
goL(1(7 + 7x) + x(7 + 7x)) = 2
goL((7 * 1 + 7x * 1) + x(7 + 7x)) = 2
goL((7 + 7x) + x(7 + 7x)) = 2
goL(7 + 7x + (7 * x + 7x * x)) = 2
goL(7 + 7x + (7x + 7x2)) = 2

Combine like terms: 7x + 7x = 14x
goL(7 + 14x + 7x2) = 2
(7 * goL + 14x * goL + 7x2 * goL) = 2
(7goL + 14goxL + 7gox2L) = 2

Solving
7goL + 14goxL + 7gox2L = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + 7goL + 14goxL + 7gox2L = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 7goL + 14goxL + 7gox2L = 0

The solution to this equation could not be determined.

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