Log(x+2)+Log(x-1)=Log(1)

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Solution for Log(x+2)+Log(x-1)=Log(1) equation:


Simplifying
Log(x + 2) + Log(x + -1) = Log(1)

Reorder the terms:
goL(2 + x) + Log(x + -1) = Log(1)
(2 * goL + x * goL) + Log(x + -1) = Log(1)
(2goL + goxL) + Log(x + -1) = Log(1)

Reorder the terms:
2goL + goxL + goL(-1 + x) = Log(1)
2goL + goxL + (-1 * goL + x * goL) = Log(1)
2goL + goxL + (-1goL + goxL) = Log(1)

Reorder the terms:
2goL + -1goL + goxL + goxL = Log(1)

Combine like terms: 2goL + -1goL = 1goL
1goL + goxL + goxL = Log(1)

Combine like terms: goxL + goxL = 2goxL
1goL + 2goxL = Log(1)

Reorder the terms for easier multiplication:
1goL + 2goxL = 1goL

Add '-1goL' to each side of the equation.
1goL + -1goL + 2goxL = 1goL + -1goL

Combine like terms: 1goL + -1goL = 0
0 + 2goxL = 1goL + -1goL
2goxL = 1goL + -1goL

Combine like terms: 1goL + -1goL = 0
2goxL = 0

Solving
2goxL = 0

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '2'.
goxL = 0

Simplifying
goxL = 0

The solution to this equation could not be determined.

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