Log(x+5)-Log(x+1)=2

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Solution for Log(x+5)-Log(x+1)=2 equation: 


Simplifying
Log(x + 5) + -1Log(x + 1) = 2

Reorder the terms:
goL(5 + x) + -1Log(x + 1) = 2
(5 * goL + x * goL) + -1Log(x + 1) = 2
(5goL + goxL) + -1Log(x + 1) = 2

Reorder the terms:
5goL + goxL + -1goL(1 + x) = 2
5goL + goxL + (1 * -1goL + x * -1goL) = 2
5goL + goxL + (-1goL + -1goxL) = 2

Reorder the terms:
5goL + -1goL + goxL + -1goxL = 2

Combine like terms: 5goL + -1goL = 4goL
4goL + goxL + -1goxL = 2

Combine like terms: goxL + -1goxL = 0
4goL + 0 = 2
4goL = 2

Solving
4goL = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '4oL'.
g = 0.5o-1L-1

Simplifying
g = 0.5o-1L-1

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