Loge(x+3)-loge(x+1)=2

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Solution for Loge(x+3)-loge(x+1)=2 equation:


Simplifying
Loge(x + 3) + -1loge(x + 1) = 2

Reorder the terms:
egoL(3 + x) + -1loge(x + 1) = 2
(3 * egoL + x * egoL) + -1loge(x + 1) = 2
(3egoL + egoxL) + -1loge(x + 1) = 2

Reorder the terms:
3egoL + egoxL + -1eglo(1 + x) = 2
3egoL + egoxL + (1 * -1eglo + x * -1eglo) = 2
3egoL + egoxL + (-1eglo + -1eglox) = 2

Reorder the terms:
-1eglo + -1eglox + 3egoL + egoxL = 2

Solving
-1eglo + -1eglox + 3egoL + egoxL = 2

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Reorder the terms:
-2 + -1eglo + -1eglox + 3egoL + egoxL = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -1eglo + -1eglox + 3egoL + egoxL = 0

The solution to this equation could not be determined.

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