M(5m+6)(4m-4)=0

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Solution for M(5m+6)(4m-4)=0 equation:



(5M+6)(4M-4)=0
We multiply parentheses ..
(+20M^2-20M+24M-24)=0
We get rid of parentheses
20M^2-20M+24M-24=0
We add all the numbers together, and all the variables
20M^2+4M-24=0
a = 20; b = 4; c = -24;
Δ = b2-4ac
Δ = 42-4·20·(-24)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$M_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$M_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$M_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-44}{2*20}=\frac{-48}{40} =-1+1/5 $
$M_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+44}{2*20}=\frac{40}{40} =1 $

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