M(s)=s(s+3)/4

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Solution for M(s)=s(s+3)/4 equation: 



(M)=M(M+3)/4

We move all terms to the left:

(M)-(M(M+3)/4)=0

We multiply all the terms by the denominator


M*4)-(M(M+3)=0

Wy multiply elements

4M^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$M=\frac{-b}{2a}=\frac{0}{8}=0$

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