M+1/2(3m+4)-5=2/3(2m-1)

Solution for M+1/2(3m+4)-5=2/3(2m-1) equation:

+1/2(3M+4)-5=2/3(2M-1)

We move all terms to the left:

+1/2(3M+4)-5-(2/3(2M-1))=0


Domain of the equation: 2(3M+4)!=0

M∈R



Domain of the equation: 3(2M-1))!=0

M∈R


We calculate fractions


(3M2/(2(3M+4)*3(2M-1)))+(-4M3/(2(3M+4)*3(2M-1)))-5=0


We calculate terms in parentheses: +(3M2/(2(3M+4)*3(2M-1))), so:

3M2/(2(3M+4)*3(2M-1))

We multiply all the terms by the denominator


3M2

We add all the numbers together, and all the variables

3M^2

Back to the equation:

+(3M^2)



We calculate terms in parentheses: +(-4M3/(2(3M+4)*3(2M-1))), so:

-4M3/(2(3M+4)*3(2M-1))

We multiply all the terms by the denominator


-4M3

We add all the numbers together, and all the variables

-4M^3

We do not support eMpression: M^3