M+1/2(3m+4)-5=2/3(2m-1)

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Solution for M+1/2(3m+4)-5=2/3(2m-1) equation:



+1/2(3M+4)-5=2/3(2M-1)
We move all terms to the left:
+1/2(3M+4)-5-(2/3(2M-1))=0
Domain of the equation: 2(3M+4)!=0
M∈R
Domain of the equation: 3(2M-1))!=0
M∈R
We calculate fractions
(3M2/(2(3M+4)*3(2M-1)))+(-4M3/(2(3M+4)*3(2M-1)))-5=0
We calculate terms in parentheses: +(3M2/(2(3M+4)*3(2M-1))), so:
3M2/(2(3M+4)*3(2M-1))
We multiply all the terms by the denominator
3M2
We add all the numbers together, and all the variables
3M^2
Back to the equation:
+(3M^2)
We calculate terms in parentheses: +(-4M3/(2(3M+4)*3(2M-1))), so:
-4M3/(2(3M+4)*3(2M-1))
We multiply all the terms by the denominator
-4M3
We add all the numbers together, and all the variables
-4M^3
We do not support eMpression: M^3

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