M3=(x2+112)

Solution for M3=(x2+112) equation:

3=(M2+112)

We move all terms to the left:

3-((M2+112))=0

We add all the numbers together, and all the variables

-((+M^2+112))+3=0


We calculate terms in parentheses: -((+M^2+112)), so:

(+M^2+112)

We get rid of parentheses

M^2+112

Back to the equation:

-(M^2+112)


We get rid of parentheses

-M^2-112+3=0

We add all the numbers together, and all the variables

-1M^2-109=0

a = -1; b = 0; c = -109;
Δ = b2-4ac
Δ = 02-4·(-1)·(-109)
Δ = -436
Delta is less than zero, so there is no solution for the equation