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4+2M^2+2M+1=0
We add all the numbers together, and all the variables
2M^2+2M+5=0
a = 2; b = 2; c = +5;
Δ = b2-4ac
Δ = 22-4·2·5
Δ = -36
Delta is less than zero, so there is no solution for the equation
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