M=2/5;b=2

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Solution for M=2/5;b=2 equation: 



=2/5M=2

We move all terms to the left:

-(2/5M)=0



Domain of the equation: 5M)!=0

M!=0/1

M!=0

M∈R



We add all the numbers together, and all the variables

-(+2/5M)=0

We get rid of parentheses

-2/5M=0

We multiply all the terms by the denominator


-2!=0

There is no solution for this equation

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