N+(3n+3)+(4n-1)=66

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Solution for N+(3n+3)+(4n-1)=66 equation: 



+(3N+3)+(4N-1)=66

We move all terms to the left:

+(3N+3)+(4N-1)-(66)=0

We get rid of parentheses

3N+4N+3-1-66=0

We add all the numbers together, and all the variables

7N-64=0

We move all terms containing N to the left, all other terms to the right

7N=64

N=64/7

N=9+1/7

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