N+(n+1)+(n+2)+(n+3)=131

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Solution for N+(n+1)+(n+2)+(n+3)=131 equation:


Simplifying
N + (n + 1) + (n + 2) + (n + 3) = 131

Reorder the terms:
N + (1 + n) + (n + 2) + (n + 3) = 131

Remove parenthesis around (1 + n)
N + 1 + n + (n + 2) + (n + 3) = 131

Reorder the terms:
N + 1 + n + (2 + n) + (n + 3) = 131

Remove parenthesis around (2 + n)
N + 1 + n + 2 + n + (n + 3) = 131

Reorder the terms:
N + 1 + n + 2 + n + (3 + n) = 131

Remove parenthesis around (3 + n)
N + 1 + n + 2 + n + 3 + n = 131

Reorder the terms:
1 + 2 + 3 + N + n + n + n = 131

Combine like terms: 1 + 2 = 3
3 + 3 + N + n + n + n = 131

Combine like terms: 3 + 3 = 6
6 + N + n + n + n = 131

Combine like terms: n + n = 2n
6 + N + 2n + n = 131

Combine like terms: 2n + n = 3n
6 + N + 3n = 131

Solving
6 + N + 3n = 131

Solving for variable 'N'.

Move all terms containing N to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + N + -6 + 3n = 131 + -6

Reorder the terms:
6 + -6 + N + 3n = 131 + -6

Combine like terms: 6 + -6 = 0
0 + N + 3n = 131 + -6
N + 3n = 131 + -6

Combine like terms: 131 + -6 = 125
N + 3n = 125

Add '-3n' to each side of the equation.
N + 3n + -3n = 125 + -3n

Combine like terms: 3n + -3n = 0
N + 0 = 125 + -3n
N = 125 + -3n

Simplifying
N = 125 + -3n

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