N+(n+1)+(n+4)=36

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Solution for N+(n+1)+(n+4)=36 equation:


Simplifying
N + (n + 1) + (n + 4) = 36

Reorder the terms:
N + (1 + n) + (n + 4) = 36

Remove parenthesis around (1 + n)
N + 1 + n + (n + 4) = 36

Reorder the terms:
N + 1 + n + (4 + n) = 36

Remove parenthesis around (4 + n)
N + 1 + n + 4 + n = 36

Reorder the terms:
1 + 4 + N + n + n = 36

Combine like terms: 1 + 4 = 5
5 + N + n + n = 36

Combine like terms: n + n = 2n
5 + N + 2n = 36

Solving
5 + N + 2n = 36

Solving for variable 'N'.

Move all terms containing N to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + N + -5 + 2n = 36 + -5

Reorder the terms:
5 + -5 + N + 2n = 36 + -5

Combine like terms: 5 + -5 = 0
0 + N + 2n = 36 + -5
N + 2n = 36 + -5

Combine like terms: 36 + -5 = 31
N + 2n = 31

Add '-2n' to each side of the equation.
N + 2n + -2n = 31 + -2n

Combine like terms: 2n + -2n = 0
N + 0 = 31 + -2n
N = 31 + -2n

Simplifying
N = 31 + -2n

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