N+(n+2)+(n+4)=106

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Solution for N+(n+2)+(n+4)=106 equation: 



+(N+2)+(N+4)=106

We move all terms to the left:

+(N+2)+(N+4)-(106)=0

We get rid of parentheses

N+N+2+4-106=0

We add all the numbers together, and all the variables

2N-100=0

We move all terms containing N to the left, all other terms to the right

2N=100

N=100/2

N=50

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