N+(n+2)+(n+4)=36

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Solution for N+(n+2)+(n+4)=36 equation:


Simplifying
N + (n + 2) + (n + 4) = 36

Reorder the terms:
N + (2 + n) + (n + 4) = 36

Remove parenthesis around (2 + n)
N + 2 + n + (n + 4) = 36

Reorder the terms:
N + 2 + n + (4 + n) = 36

Remove parenthesis around (4 + n)
N + 2 + n + 4 + n = 36

Reorder the terms:
2 + 4 + N + n + n = 36

Combine like terms: 2 + 4 = 6
6 + N + n + n = 36

Combine like terms: n + n = 2n
6 + N + 2n = 36

Solving
6 + N + 2n = 36

Solving for variable 'N'.

Move all terms containing N to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + N + -6 + 2n = 36 + -6

Reorder the terms:
6 + -6 + N + 2n = 36 + -6

Combine like terms: 6 + -6 = 0
0 + N + 2n = 36 + -6
N + 2n = 36 + -6

Combine like terms: 36 + -6 = 30
N + 2n = 30

Add '-2n' to each side of the equation.
N + 2n + -2n = 30 + -2n

Combine like terms: 2n + -2n = 0
N + 0 = 30 + -2n
N = 30 + -2n

Simplifying
N = 30 + -2n

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