N+20=(3n-20)/2

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Solution for N+20=(3n-20)/2 equation: 



+20=(3N-20)/2

We move all terms to the left:

+20-((3N-20)/2)=0

We multiply all the terms by the denominator


-((3N-20)+20*2)=0



We calculate terms in parentheses: -((3N-20)+20*2), so:

(3N-20)+20*2

We add all the numbers together, and all the variables

(3N-20)+40

We get rid of parentheses

3N-20+40

We add all the numbers together, and all the variables

3N+20

Back to the equation:

-(3N+20)



We get rid of parentheses

-3N-20=0

We move all terms containing N to the left, all other terms to the right

-3N=20

N=20/-3

N=-6+2/3

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