N+2=1/3(3n+6)

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Solution for N+2=1/3(3n+6) equation: 



+2=1/3(3N+6)

We move all terms to the left:

+2-(1/3(3N+6))=0



Domain of the equation: 3(3N+6))!=0

N∈R



We multiply all the terms by the denominator


-(1+2*3(3N+6))=0



We calculate terms in parentheses: -(1+2*3(3N+6)), so:

1+2*3(3N+6)

determiningTheFunctionDomain
2*3(3N+6)+1

Wy multiply elements

6N(3+1

Back to the equation:

-(6N(3+1)



We add all the numbers together, and all the variables

-(6N4=0

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