N+3(-3+n)=3(1+n)-2n

Solution for N+3(-3+n)=3(1+n)-2n equation:

+3(-3+N)=3(1+N)-2N

We move all terms to the left:

+3(-3+N)-(3(1+N)-2N)=0

We add all the numbers together, and all the variables

3(N-3)-(3(N+1)-2N)=0

We multiply parentheses

3N-(3(N+1)-2N)-9=0


We calculate terms in parentheses: -(3(N+1)-2N), so:

3(N+1)-2N

We add all the numbers together, and all the variables

-2N+3(N+1)

We multiply parentheses

-2N+3N+3

We add all the numbers together, and all the variables

N+3

Back to the equation:

-(N+3)


We get rid of parentheses

3N-N-3-9=0

We add all the numbers together, and all the variables

2N-12=0

We move all terms containing N to the left, all other terms to the right

2N=12

N=12/2

N=6