N+3(n-4)=20

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Solution for N+3(n-4)=20 equation: 


Simplifying
N + 3(n + -4) = 20

Reorder the terms:
N + 3(-4 + n) = 20
N + (-4 * 3 + n * 3) = 20
N + (-12 + 3n) = 20

Reorder the terms:
-12 + N + 3n = 20

Solving
-12 + N + 3n = 20

Solving for variable 'N'.

Move all terms containing N to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + N + 12 + 3n = 20 + 12

Reorder the terms:
-12 + 12 + N + 3n = 20 + 12

Combine like terms: -12 + 12 = 0
0 + N + 3n = 20 + 12
N + 3n = 20 + 12

Combine like terms: 20 + 12 = 32
N + 3n = 32

Add '-3n' to each side of the equation.
N + 3n + -3n = 32 + -3n

Combine like terms: 3n + -3n = 0
N + 0 = 32 + -3n
N = 32 + -3n

Simplifying
N = 32 + -3n

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