N+3n-2=5n+7+2(2n+1)

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Solution for N+3n-2=5n+7+2(2n+1) equation: 



+3N-2=5N+7+2(2N+1)

We move all terms to the left:

+3N-2-(5N+7+2(2N+1))=0



We calculate terms in parentheses: -(5N+7+2(2N+1)), so:

5N+7+2(2N+1)

determiningTheFunctionDomain
5N+2(2N+1)+7

We multiply parentheses

5N+4N+2+7

We add all the numbers together, and all the variables

9N+9

Back to the equation:

-(9N+9)



We get rid of parentheses

3N-9N-9-2=0

We add all the numbers together, and all the variables

-6N-11=0

We move all terms containing N to the left, all other terms to the right

-6N=11

N=11/-6

N=-1+5/6

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