N+n+1+n+2=4n-5

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Solution for N+n+1+n+2=4n-5 equation: 



+N+1+N+2=4N-5

We move all terms to the left:

+N+1+N+2-(4N-5)=0

We add all the numbers together, and all the variables

2N-(4N-5)+3=0

We get rid of parentheses

2N-4N+5+3=0

We add all the numbers together, and all the variables

-2N+8=0

We move all terms containing N to the left, all other terms to the right

-2N=-8

N=-8/-2

N=+4

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