N+n+1+n+2=4n-5

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Solution for N+n+1+n+2=4n-5 equation:



+N+1+N+2=4N-5
We move all terms to the left:
+N+1+N+2-(4N-5)=0
We add all the numbers together, and all the variables
2N-(4N-5)+3=0
We get rid of parentheses
2N-4N+5+3=0
We add all the numbers together, and all the variables
-2N+8=0
We move all terms containing N to the left, all other terms to the right
-2N=-8
N=-8/-2
N=+4

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