N+n+2=3(n+4)+7

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Solution for N+n+2=3(n+4)+7 equation:



+N+2=3(N+4)+7
We move all terms to the left:
+N+2-(3(N+4)+7)=0
We calculate terms in parentheses: -(3(N+4)+7), so:
3(N+4)+7
We multiply parentheses
3N+12+7
We add all the numbers together, and all the variables
3N+19
Back to the equation:
-(3N+19)
We get rid of parentheses
N-3N-19+2=0
We add all the numbers together, and all the variables
-2N-17=0
We move all terms containing N to the left, all other terms to the right
-2N=17
N=17/-2
N=-8+1/2

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