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4-49N^2=0
a = -49; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-49)·4
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$N_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$N_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$N_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28}{2*-49}=\frac{-28}{-98} =2/7 $$N_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28}{2*-49}=\frac{28}{-98} =-2/7 $
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