N=(2-1)+(s+1)

Solution for N=(2-1)+(s+1) equation:

=(2-1)+(N+1)

We move all terms to the left:

-((2-1)+(N+1))=0

We add all the numbers together, and all the variables

-(1+(N+1))=0


We calculate terms in parentheses: -(1+(N+1)), so:

1+(N+1)

determiningTheFunctionDomain
(N+1)+1

We get rid of parentheses

N+1+1

We add all the numbers together, and all the variables

N+2

Back to the equation:

-(N+2)


We get rid of parentheses

-N-2=0

We add all the numbers together, and all the variables

-1N-2=0

We move all terms containing N to the left, all other terms to the right

-N=2

N=2/-1

N=-2