N=7/5(n-53)n=

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Solution for N=7/5(n-53)n= equation: 



=7/5(N-53)N=

We move all terms to the left:

-(7/5(N-53)N)=0



Domain of the equation: 5(N-53)N)!=0

N∈R



We multiply all the terms by the denominator


-(7=0

We add all the numbers together, and all the variables

=0

N=0/1

N=0

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