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N2=7+9
We move all terms to the left:
N2-(7+9)=0
We add all the numbers together, and all the variables
N2-16=0
We add all the numbers together, and all the variables
N^2-16=0
a = 1; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·1·(-16)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$N_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$N_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$N_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*1}=\frac{-8}{2} =-4 $$N_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*1}=\frac{8}{2} =4 $
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