O.2(x+50)-6=0.4(3x+20)

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Solution for O.2(x+50)-6=0.4(3x+20) equation:



.2(O+50)-6=0.4(3O+20)
We move all terms to the left:
.2(O+50)-6-(0.4(3O+20))=0
We multiply parentheses
0.2O-(0.4(3O+20))+10-6=0
We calculate terms in parentheses: -(0.4(3O+20)), so:
0.4(3O+20)
We multiply parentheses
1.2O+8
Back to the equation:
-(1.2O+8)
We add all the numbers together, and all the variables
0.2O-(1.2O+8)+4=0
We get rid of parentheses
0.2O-1.2O-8+4=0
We add all the numbers together, and all the variables
-1O-4=0
We move all terms containing O to the left, all other terms to the right
-O=4
O=4/-1
O=-4

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