P(11)=5(x2+1)+16

Solution for P(11)=5(x2+1)+16 equation:

(11)=5(P2+1)+16

We move all terms to the left:

(11)-(5(P2+1)+16)=0

We add all the numbers together, and all the variables

-(5(+P^2+1)+16)+11=0


We calculate terms in parentheses: -(5(+P^2+1)+16), so:

5(+P^2+1)+16

We multiply parentheses

5P^2+5+16

We add all the numbers together, and all the variables

5P^2+21

Back to the equation:

-(5P^2+21)


We get rid of parentheses

-5P^2-21+11=0

We add all the numbers together, and all the variables

-5P^2-10=0

a = -5; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·(-5)·(-10)
Δ = -200
Delta is less than zero, so there is no solution for the equation