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(P)=-40P^2+2000P-16.000
We move all terms to the left:
(P)-(-40P^2+2000P-16.000)=0
We get rid of parentheses
40P^2-2000P+P+16.000=0
We add all the numbers together, and all the variables
40P^2-1999P+16=0
a = 40; b = -1999; c = +16;
Δ = b2-4ac
Δ = -19992-4·40·16
Δ = 3993441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1999)-\sqrt{3993441}}{2*40}=\frac{1999-\sqrt{3993441}}{80} $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1999)+\sqrt{3993441}}{2*40}=\frac{1999+\sqrt{3993441}}{80} $
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