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(P)=4P^2-4P
We move all terms to the left:
(P)-(4P^2-4P)=0
We get rid of parentheses
-4P^2+P+4P=0
We add all the numbers together, and all the variables
-4P^2+5P=0
a = -4; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-4)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-4}=\frac{-10}{-8} =1+1/4 $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-4}=\frac{0}{-8} =0 $
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