P+1/p-2=p+1/p-3

Solution for P+1/p-2=p+1/p-3 equation:

+1/P-2=P+1/P-3

We move all terms to the left:

+1/P-2-(P+1/P-3)=0


Domain of the equation: P!=0

P∈R



Domain of the equation: P-3)!=0

P∈R


We get rid of parentheses

1/P-P-1/P+3-2=0

We multiply all the terms by the denominator


-P*P+3*P-2*P+1-1=0

We add all the numbers together, and all the variables

P-P*P=0

Wy multiply elements

-1P^2+P=0

a = -1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-1)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-1}=\frac{-2}{-2}
=1
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-1}=\frac{0}{-2}
=0
$