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1-P2=-0.24
We move all terms to the left:
1-P2-(-0.24)=0
We add all the numbers together, and all the variables
-1P^2+1.24=0
a = -1; b = 0; c = +1.24;
Δ = b2-4ac
Δ = 02-4·(-1)·1.24
Δ = 4.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4.96}}{2*-1}=\frac{0-\sqrt{4.96}}{-2} =-\frac{\sqrt{}}{-2} $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4.96}}{2*-1}=\frac{0+\sqrt{4.96}}{-2} =\frac{\sqrt{}}{-2} $
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