P4(2x-3)=2(x+15)

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Solution for P4(2x-3)=2(x+15) equation:



4(2P-3)=2(P+15)
We move all terms to the left:
4(2P-3)-(2(P+15))=0
We multiply parentheses
8P-(2(P+15))-12=0
We calculate terms in parentheses: -(2(P+15)), so:
2(P+15)
We multiply parentheses
2P+30
Back to the equation:
-(2P+30)
We get rid of parentheses
8P-2P-30-12=0
We add all the numbers together, and all the variables
6P-42=0
We move all terms containing P to the left, all other terms to the right
6P=42
P=42/6
P=7

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