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=(P+2)(P-2)(P2+4)
We move all terms to the left:
-((P+2)(P-2)(P2+4))=0
We add all the numbers together, and all the variables
-((P+2)(P-2)(+P^2+4))=0
We use the square of the difference formula
P^2+4=0
a = 1; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·1·4
Δ = -16
Delta is less than zero, so there is no solution for the equation
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