P=2(l+l+4)

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Solution for P=2(l+l+4) equation:



=2(P+P+4)
We move all terms to the left:
-(2(P+P+4))=0
We add all the numbers together, and all the variables
-(2(2P+4))=0
We calculate terms in parentheses: -(2(2P+4)), so:
2(2P+4)
We multiply parentheses
4P+8
Back to the equation:
-(4P+8)
We get rid of parentheses
-4P-8=0
We move all terms containing P to the left, all other terms to the right
-4P=8
P=8/-4
P=-2

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