P=6,7p2+p

Solution for P=6,7p2+p equation:

=6.7P^2+P

We move all terms to the left:

-(6.7P^2+P)=0

We get rid of parentheses

-6.7P^2-P=0

We add all the numbers together, and all the variables

-6.7P^2-1P=0

a = -6.7; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-6.7)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-6.7}=\frac{0}{-13.4}
=0
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-6.7}=\frac{2}{-13.4}
=-2/13.4
$