P=x+(2x-2)+(3x-6)

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Solution for P=x+(2x-2)+(3x-6) equation: 



=P+(2P-2)+(3P-6)

We move all terms to the left:

-(P+(2P-2)+(3P-6))=0



We calculate terms in parentheses: -(P+(2P-2)+(3P-6)), so:

P+(2P-2)+(3P-6)

We get rid of parentheses

P+2P+3P-2-6

We add all the numbers together, and all the variables

6P-8

Back to the equation:

-(6P-8)



We get rid of parentheses

-6P+8=0

We move all terms containing P to the left, all other terms to the right

-6P=-8

P=-8/-6

P=1+1/3

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