Q-2m-5m-8=3+(-7)+m

Solution for Q-2m-5m-8=3+(-7)+m equation:

-2Q-5Q-8=3+(-7)+Q

We move all terms to the left:

-2Q-5Q-8-(3+(-7)+Q)=0

We add all the numbers together, and all the variables

-7Q-(3+(-7)+Q)-8=0


We calculate terms in parentheses: -(3+(-7)+Q), so:

3+(-7)+Q

determiningTheFunctionDomain
Q+3+(-7)

We add all the numbers together, and all the variables

Q-4

Back to the equation:

-(Q-4)


We get rid of parentheses

-7Q-Q+4-8=0

We add all the numbers together, and all the variables

-8Q-4=0

We move all terms containing Q to the left, all other terms to the right

-8Q=4

Q=4/-8

Q=-1/2