Q=25-(25/12)p

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Solution for Q=25-(25/12)p equation: 



=25-(25/12)Q

We move all terms to the left:

-(25-(25/12)Q)=0



Domain of the equation: 12)Q)!=0

Q!=0/1

Q!=0

Q∈R



We add all the numbers together, and all the variables

-(25-(+25/12)Q)=0

We multiply all the terms by the denominator


-(25-(+25=0

We add all the numbers together, and all the variables

=0

Q=0/1

Q=0

Równanie nie ma rozwiązania

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