Q=C(v1-v2)

Solution for Q=C(v1-v2) equation:

=(Q1-Q2)

We move all terms to the left:

-((Q1-Q2))=0

We add all the numbers together, and all the variables

-((+Q-1Q^2))=0


We calculate terms in parentheses: -((+Q-1Q^2)), so:

(+Q-1Q^2)

We get rid of parentheses

-1Q^2+Q

Back to the equation:

-(-1Q^2+Q)


We get rid of parentheses

1Q^2-Q=0

We add all the numbers together, and all the variables

Q^2-1Q=0

a = 1; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·1·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$Q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*1}=\frac{0}{2}
=0
$
$Q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*1}=\frac{2}{2}
=1
$