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(R)=-0.4R^2+64R-2400
We move all terms to the left:
(R)-(-0.4R^2+64R-2400)=0
We get rid of parentheses
0.4R^2-64R+R+2400=0
We add all the numbers together, and all the variables
0.4R^2-63R+2400=0
a = 0.4; b = -63; c = +2400;
Δ = b2-4ac
Δ = -632-4·0.4·2400
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-\sqrt{129}}{2*0.4}=\frac{63-\sqrt{129}}{0.8} $$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+\sqrt{129}}{2*0.4}=\frac{63+\sqrt{129}}{0.8} $
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