R(x)=(-80x+4000)(0.5x+1)

Solution for R(x)=(-80x+4000)(0.5x+1) equation:

(R)=(-80R+4000)(0.5R+1)

We move all terms to the left:

(R)-((-80R+4000)(0.5R+1))=0

We multiply parentheses ..

-((+0R^2-80R+0R+4000))+R=0


We calculate terms in parentheses: -((+0R^2-80R+0R+4000)), so:

(+0R^2-80R+0R+4000)

We get rid of parentheses

0R^2-80R+0R+4000

We add all the numbers together, and all the variables

R^2-79R+4000

Back to the equation:

-(R^2-79R+4000)


We add all the numbers together, and all the variables

R-(R^2-79R+4000)=0

We get rid of parentheses

-R^2+R+79R-4000=0

We add all the numbers together, and all the variables

-1R^2+80R-4000=0

a = -1; b = 80; c = -4000;
Δ = b2-4ac
Δ = 802-4·(-1)·(-4000)
Δ = -9600
Delta is less than zero, so there is no solution for the equation