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(R)=R-0.01R^2
We move all terms to the left:
(R)-(R-0.01R^2)=0
We get rid of parentheses
0.01R^2-R+R=0
We add all the numbers together, and all the variables
0.01R^2=0
a = 0.01; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·0.01·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$R=\frac{-b}{2a}=\frac{0}{0.02}=0$
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