R+(r+3)+2(r+3)=57

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Solution for R+(r+3)+2(r+3)=57 equation: 



+(R+3)+2(R+3)=57

We move all terms to the left:

+(R+3)+2(R+3)-(57)=0

We multiply parentheses

(R+3)+2R+6-57=0

We get rid of parentheses

R+2R+3+6-57=0

We add all the numbers together, and all the variables

3R-48=0

We move all terms containing R to the left, all other terms to the right

3R=48

R=48/3

R=16

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