R-8+r-12=-4(r-7)+12(r-2)

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Solution for R-8+r-12=-4(r-7)+12(r-2) equation: 



-8+R-12=-4(R-7)+12(R-2)

We move all terms to the left:

-8+R-12-(-4(R-7)+12(R-2))=0

We add all the numbers together, and all the variables

R-(-4(R-7)+12(R-2))-20=0



We calculate terms in parentheses: -(-4(R-7)+12(R-2)), so:

-4(R-7)+12(R-2)

We multiply parentheses

-4R+12R+28-24

We add all the numbers together, and all the variables

8R+4

Back to the equation:

-(8R+4)



We get rid of parentheses

R-8R-4-20=0

We add all the numbers together, and all the variables

-7R-24=0

We move all terms containing R to the left, all other terms to the right

-7R=24

R=24/-7

R=-3+3/7

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