R=-p2+30p

Solution for R=-p2+30p equation:

=-R2+30R

We move all terms to the left:

-(-R2+30R)=0

We add all the numbers together, and all the variables

-(-1R^2+30R)=0

We get rid of parentheses

1R^2-30R=0

We add all the numbers together, and all the variables

R^2-30R=0

a = 1; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·1·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*1}=\frac{0}{2}
=0
$
$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*1}=\frac{60}{2}
=30
$