S(f+2)=2(3-f)

Solution for S(f+2)=2(3-f) equation:

(S+2)=2(3-S)

We move all terms to the left:

(S+2)-(2(3-S))=0

We add all the numbers together, and all the variables

(S+2)-(2(-1S+3))=0

We get rid of parentheses

S-(2(-1S+3))+2=0


We calculate terms in parentheses: -(2(-1S+3)), so:

2(-1S+3)

We multiply parentheses

-2S+6

Back to the equation:

-(-2S+6)


We get rid of parentheses

S+2S-6+2=0

We add all the numbers together, and all the variables

3S-4=0

We move all terms containing S to the left, all other terms to the right

3S=4

S=4/3

S=1+1/3