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(S)=(2S+3)/(5-4S)
We move all terms to the left:
(S)-((2S+3)/(5-4S))=0
Domain of the equation: (5-4S))!=0We add all the numbers together, and all the variables
We move all terms containing S to the left, all other terms to the right
-4S)!=-5
S!=-5/1
S!=-5
S∈R
S-((2S+3)/(-4S+5))=0
We multiply all the terms by the denominator
S*(-4S+5))-((2S+3)=0
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